How do I run a command on multiple files

This is pretty basic, I have a folder with several subfolders of JS files and i want to run Google’s Clojure compiler on all of the files in those folders. The command to process a single file is as follows:

java -jar compiler.jar --js filename.js --js_output_file newfilename.js

How do I modify this to run on every JS file in my directory structure?

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Answers:

Method 1

Method 2

Answers:

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Method 1

You can use find:

find . -name "*.js" -exec java -jar compiler.jar --js {} --js_output_file new{} ;

Method 2

You can also use a simple for loop, especially if the files are within a single directory (no subdirectories). It can be modified to work with subdirectories as well.

Without recursion:

for filename in ./*.js
do
    java -jar compiler.jar --js "${filename}" --js_output_file "new${filename}"
done

or as an equivalent one-liner:

for filename in ./*.js; do java -jar compiler.jar --js "${filename}" --js_output_file "new${filename}"; done

To recurse into subdirectories (requires GNU bash 4.0 or newer) (thanks @ChrisDown):

shopt -s globstar
for filename in ./**/*.js; do
    java -jar compiler.jar --js "${filename}" --js_output_file "new${filename}"
done

All methods was sourced from stackoverflow.com or stackexchange.com, is licensed under cc by-sa 2.5, cc by-sa 3.0 and cc by-sa 4.0

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