How to determine callee function name in a script

To make it short, doing something like:

-bash$ function tt
{
 echo $0;
}

-bash$ tt

$0 will return -bash, but how to get the function name called, i.e. tt in this example instead?

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Answers:

Method 1

Method 2

Method 3

Answers:

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Method 1

In bash, use FUNCNAME array:

tt() {
  printf '%sn' "$FUNCNAME"
}

With some ksh implementations:

tt() { printf '%sn' "$0"; }

In ksh93:

tt() { printf '%sn' "${.sh.fun}"; }

From ksh93d and above, you can also use $0 inside function to get the function name, but you must define function using function name { ...; } form.

In zsh, you can use funcstack array:

tt() { print -rl -- $funcstack[1]; }

or $0 inside function.

In fish:

function tt
  printf '%sn' "$_"
end

Method 2

In bash, you can use ${FUNCNAME[0]}.

Method 3

function tt { echo ${FUNCNAME}; }

does it on my CentOS 6 box.

All methods was sourced from stackoverflow.com or stackexchange.com, is licensed under cc by-sa 2.5, cc by-sa 3.0 and cc by-sa 4.0

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