How to display fields from the loop in two separate divs

I’m making this website where i’m displaying things in two colums: on the left, a list of titles, when you click them, it expands a text and on the right it show the corresponding images.
To do so, I use a css grid.
Here is my code that I use to generate my blog posts and display the corresponding images.
My issue there is that .four is supposed to be on the left, that is correct, and .five should be on the left, but it’s not since .five is generated under .four (left). How can I write this correctly so .five is not a child of .four and stays a child of my .wrapper but is keeping the id() order fine?

 <div class="wrapper-top">
    <div class="four">
    <?php
// the query
    $all_posts = new WP_Query( array( 'post_type' => 'post', 'post_status' => 'publish', 'posts_per_page' => -1 ) );

    if ( $all_posts->have_posts() ) :
        ?>

        <ul>
            <?php while ( $all_posts->have_posts() ) : $all_posts->the_post();  global $post;
                ?>

                <li class='sub-menu'> <a href='#' class="exposition"  data-id="<?php the_id();?>"><?php the_title(); ?></a> <ul>
                    <li><?php the_content(); ?>
                    <?php the_id();?>
                </li>
            </ul>
        </li>
    </ul>

    <div class="five"> 
        <?php $images = get_field('gallery');
        if( $images ): ?>
            <div class="slide-photos" id="<?php the_id();?>" data-id="<?php the_id();?>"> 
                <?php foreach( $images as $image ): ?>
                    <div class="photos-ind"><img id="<?php the_id();?>" class="slide-photos" src="<?php echo esc_url($image['sizes']['thumbnail']); ?>" data-id="<?php the_id();?>"/></div>
                    <?php endforeach; ?></div>
                <?php endif; ?>
            </div>
        <?php endwhile; ?>
        <?php else : ?>
        <?php endif; ?>
    </div>
</div>

Thanks a lot.

Answers:

Thank you for visiting the Q&A section on Magenaut. Please note that all the answers may not help you solve the issue immediately. So please treat them as advisements. If you found the post helpful (or not), leave a comment & I’ll get back to you as soon as possible.

Method 1

A simple solution would be just run the loop twice.

    <?php // set loop $args here so they're in once place ?>

    <div class="four">
        <?php // run the loop once with $args, output left side items ?>
    </div>
    <div class="five">
        <?php // run the loop again with $args, output right side items ?>
    </div>

All methods was sourced from stackoverflow.com or stackexchange.com, is licensed under cc by-sa 2.5, cc by-sa 3.0 and cc by-sa 4.0