Print file content without the first and last lines

Is there a simple way I can echo a file, skipping the first and last lines? I was looking at piping from head into tail, but for those it seems like I would have to know the total lines from the outset. I was also looking at split, but I don’t see a way to do it with that either.

Answers:

Thank you for visiting the Q&A section on Magenaut. Please note that all the answers may not help you solve the issue immediately. So please treat them as advisements. If you found the post helpful (or not), leave a comment & I’ll get back to you as soon as possible.

Method 1

Just with sed, without any pipes :

sed '1d;$d' file.txt

NOTE

  • 1 mean first line
  • d mean delete
  • ; is the separator for 2 commands
  • $ mean last line

Method 2

You don’t need to know the number of lines in advance. tail and head can take an offset from the beginning or end of the file respectively.

This pipe starts at the second line of the file (skipping the first line) and stops at the last but one (skipping the final line). To skip more than one line at the beginning or end, adjust the numbers accordingly.

tail -n +2 file.txt | head -n -1

doing it the other way round, works the same, of course:

head -n -1 file.txt | tail -n +2

Method 3

Here is how to do it with awk:

awk 'NR>2 {print t} {t=$0}'

Also another way for sed:

sed '1d;x' file.txt

x is advanced sed command, it switches current line with the previous one: current goes into the buffer and previous goes to the screen and so on while sed processing stream line by line (this is why the first line will be blank).

awk solution on each step (line) puts current line into the variable and starts printing it out only after the second line is passed by. Thus, we got shitfed sequence of lines on the screen from the second to the last but one. Last line is omitted becasue the line is in the variable and should be printed only on the next step, but all steps already run out and we never see the line on the screen.

Same idea in the perl:

perl -ne 'print $t if $.>2 ; $t=$_' file.txt

$. stands for line number and $_ for current line.
perl -n is shortcut for while(<..>) {..} structure and -e is for inline script.

Method 4

For Mac users:

On Mac, head -n -1 doesn’t work. Instead, reverse the file, chop off the first line, then reverse it back:

tail -r file.txt | tail -n +2 | tail -r

Explanation:

  1. tail -r : reverses the order of lines in its input
  2. tail -n +2 : prints all the lines starting from the second line in its input

Method 5

In python i would do like this.

#!/usr/bin/python3
import re
import sys
file = sys.argv[1]
with open(file, 'r') as f:
    L = []
    for line in f:
        line = re.sub(r'n', r'', line)
        L.append(line)
    print('n'.join(L[1:-1]))

Paste the above code into a file and name it as script.py. Run the script against the file you want to check with.

python3 script.py /path/to/the/file

Example:

$ cat file
foo
apple
banana
bar
$ python3 script.py file
apple
banana


All methods was sourced from stackoverflow.com or stackexchange.com, is licensed under cc by-sa 2.5, cc by-sa 3.0 and cc by-sa 4.0

0 0 votes
Article Rating
Subscribe
Notify of
guest

0 Comments
Oldest
Newest Most Voted
Inline Feedbacks
View all comments
0
Would love your thoughts, please comment.x
()
x