I’m a new Python programmer who is making the leap from 2.6.4 to 3.1.1. Everything has gone fine until I tried to use the ‘else if’ statement. The interpreter gives me a syntax error after the ‘if’ in ‘else if’ for a reason I can’t seem to figure out.
I have this image with size 128 x 128 pixels and RGBA stored as byte values in my memory. But
def isBig(x): if x > 4: return 'apple' else: return 'orange' This works: if isBig(y): return isBig(y) This does NOT work: if fruit = isBig(y): return fruit Why doesn’t the 2nd one work!? I want a 1-liner. Except, the 1st one will call the function TWICE. How to make it 1 liner, without calling the … Read more
I have two numpy arrays of different shapes, but with the same length (leading dimension). I want to shuffle each of them, such that corresponding elements continue to correspond — i.e. shuffle them in unison with respect to their leading indices.
I am using the following code to plot a bar-chart:
I’m playing around with a little web app in web.py, and am setting up a url to return a JSON object. What’s the best way to convert a SQL table to JSON using python?
I am using python and Qt Designer to implement loading tiff images and to enable Pan and Zoom on some mouse event (wheel – zoom, press wheel – pan).
How do I get values from form fields in the django framework? I want to do this in views, not in templates…
So I’m learning Python. I am going through the lessons and ran into a problem where I had to condense a great many target.write() into a single write(), while having a "n" between each user input variable(the object of write()).
This seems like a ridiculously easy question… but I’m not seeing the easy answer I was expecting.
