How to truncate the time on a datetime object?
What is a classy way to way truncate a python datetime object?
What is a classy way to way truncate a python datetime object?
I know about plot_date() but is there a bar_date() out there?
This is just another post on pytz.
I import a dataframe via read_csv, but for some reason can’t extract the year or month from the series df['date'], trying that gives AttributeError: 'Series' object has no attribute 'year':
I have a time difference
Given two datetimes (start_date and end_date), I’d like to generate a list of other datetimes between these two dates, the new datetimes being separated by a variable interval. e.g. every 4 days between 2011-10-10 and 2011-12-12 or every 8 hours between now and tomorrow 19p.m.
I’m adding UTC time strings to Bitbucket API responses that currently only contain Amsterdam (!) time strings. For consistency with the UTC time strings returned elsewhere, the desired format is 2011-11-03 11:07:04 (followed by +00:00, but that’s not germane).
Is there a format for printing Python datetimes that won’t use zero-padding on dates and times?
I have used a ruby script to convert iso time stamp to epoch, the files that I am parsing has following time stamp structure:
The first is to use the localize() method provided by the pytz library. This is used to localize a naive datetime (datetime with no timezone information):