Convert list into a dictionary
returns a list of tuples, where the i-th tuple contains the i-th element from each of the arguments
returns a list of tuples, where the i-th tuple contains the i-th element from each of the arguments
I have a dict and would like to remove all the keys for which there are empty value strings.
I want to sort a dictionary of lists, by third item in each list. It’s easy enough sorting a dictionary by value when the value is just a single number or string, but this list thing has me baffled.
I am trying to take a dictionary and append it to a list. The dictionary then changes values and then is appended again in a loop. It seems that every time I do this, all the dictionaries in the list change their values to match the one that was just appended.
How do I find out if a key in a dictionary has already been set to a non-None value?
I am writing a program that stores data in a dictionary object, but this data needs to be saved at some point during the program execution and loaded back into the dictionary object when the program is run again.
How would I convert a dictionary object into a string that can be written to a file and loaded back into a dictionary object? This will hopefully support dictionaries containing dictionaries.
I have a very large collection of (p, q) tuples that I would like to convert into a dictionary of lists where the first item in each tuple is a key that indexes a list that contains q.
I want to create a python dictionary that returns me the key value for the keys are missing from the dictionary.