Convert Django Model object to dict with all of the fields intact
How does one convert a django Model object to a dict with all of its fields? All ideally includes foreign keys and fields with editable=False.
How does one convert a django Model object to a dict with all of its fields? All ideally includes foreign keys and fields with editable=False.
When I read Django code I often see in models what is called a “slug”. I am not quite sure what this is, but I do know it has something to do with URLs. How and when is this slug-thing supposed to be used?
I’m writing a Django Middleware class that I want to execute only once at startup, to initialise some other arbritary code. I’ve followed the very nice solution posted by sdolan here, but the “Hello” message is output to the terminal twice. E.g.
How do I get user’s IP in django?
After creating a NumPy array, and saving it as a Django context variable, I receive the following error when loading the webpage:
Given a URL like the following, how can I parse the value of the query parameters? For example, in this case I want the value of some_key .
Before saving model I’m re-size a picture. But how can I check if new picture added or just description updated, so I can skip rescaling every time the model is saved?
What are the differences of these three static url?
Let’s say I have the following models
I have a Model as follows: