Pass a list to a function to act as multiple arguments
In a function that expects a list of items, how can I pass a Python list item without getting an error?
In a function that expects a list of items, how can I pass a Python list item without getting an error?
I have this nested list:
What are the advantages of NumPy over regular Python lists?
I have to search through a list and replace all occurrences of one element with another. So far my attempts in code are getting me nowhere, what is the best way to do this?
How do I iterate over a list in reverse in Python?
How do I make a for loop or a list comprehension so that every iteration gives me two elements? l = [1,2,3,4,5,6] for i,k in ???: print str(i), '+', str(k), '=', str(i+k) Output: 1+2=3 3+4=7 5+6=11 Answers: Thank you for visiting the Q&A section on Magenaut. Please note that all the answers may not help … Read more
I have a list of Python objects that I want to sort by a specific attribute of each object:
What is the most efficient way to rotate a list in python?
Right now I have something like this:
Note: There is a subtlety when the sequence is being modified by the
loop (this can only occur for mutable sequences, i.e. lists). An
internal counter is used to keep track of which item is used next, and
this is incremented on each iteration. When this counter has reached
the length of the sequence the loop terminates. This means that if the
suite deletes the current (or a previous) item from the sequence, the
next item will be skipped (since it gets the index of the current item
which has already been treated). Likewise, if the suite inserts an
item in the sequence before the current item, the current item will be
treated again the next time through the loop. This can lead to nasty
bugs that can be avoided by making a temporary copy using a slice of
the whole sequence, e.g.,
Python 3.0 range() now behaves like xrange() used to behave, except it works with values of arbitrary size. The latter no longer exists.