list to dictionary conversion with multiple values per key?
I have a Python list which holds pairs of key/value:
I have a Python list which holds pairs of key/value:
I need to verify if a list is a subset of another – a boolean return is all I seek.
I have the following code inside a while loop. if gender == 0 and len(men) < 51 : height = float((random.uniform(1.3, 1.9) + (random.randint(10, 20)/100.)).__format__('.2f')) weight = float((random.uniform(45, 100) * height).__format__('.2f')) attr['height'] = height attr['weight'] = weight men.append(attr) So this code always gives some random height and random weight. But outsite de loop (when it … Read more
I got this list:
Given a string that is a sequence of several values separated by a commma:
I have an n-by-m Pandas DataFrame df defined as follows. (I know this is not the best way to do it. It makes sense for what I’m trying to do in my actual code, but that would be TMI for this post so just take my word that this approach works in my particular scenario.)
Tuples are faster than lists. If you’re defining a constant set of values and all you’re ever going to do with it is iterate through it, use a tuple instead of a list.
I have two lists of objects. Each list is already sorted by a property of the object that is of the datetime type. I would like to combine the two lists into one sorted list. Is the best way just to do a sort or is there a smarter way to do this in Python?
Given the list ['a','ab','abc','bac'], I want to compute a list with strings that have 'ab' in them. I.e. the result is ['ab','abc']. How can this be done in Python?
I’ve got a list of integers and I want to be able to identify contiguous blocks of duplicates: that is, I want to produce an order-preserving list of duples where each duples contains (int_in_question, number of occurrences).