Finding the index of an item in a list
Given a list ["foo", "bar", "baz"] and an item in the list "bar", how do I get its index 1?
Given a list ["foo", "bar", "baz"] and an item in the list "bar", how do I get its index 1?
I have two lists in Python:
While using new_list = my_list, any modifications to new_list changes my_list every time. Why is this, and how can I clone or copy the list to prevent it?
I have a Python script which takes as input a list of integers, which I need to work with four integers at a time. Unfortunately, I don’t have control of the input, or I’d have it passed in as a list of four-element tuples. Currently, I’m iterating over it this way:
I have a complex dictionary structure which I would like to access via a list of keys to address the correct item.
What is the Pythonic approach to achieve the following?
I have a list of objects and I want to shuffle them. I thought I could use the random.shuffle method, but this seems to fail when the list is of objects. Is there a method for shuffling objects or another way around this?
Python docs says that slicing a list returns a new list.
Now if a “new” list is being returned I’ve the following questions related to “Assignment to slices”
index() will give the first occurrence of an item in a list. Is there a neat trick which returns all indices in a list for an element?
While looping over a list in Python, I was unable to modify the elements without a list comprehension. For reference: li = ["spam", "eggs"] for i in li: i = "foo" li ["spam", "eggs"] li = ["foo" for i in li] li ["foo", "foo"] So, why can’t I modify elements through a loop in Python? … Read more