Find the nth occurrence of substring in a string
This seems like it should be pretty trivial, but I am new at Python and want to do it the most Pythonic way.
This seems like it should be pretty trivial, but I am new at Python and want to do it the most Pythonic way.
How do I efficiently append one string to another? Are there any faster alternatives to:
I want to I check whether a string is in ASCII or not.
I have data which is being accessed via http request and is sent back by the server in a comma separated format, I have the following code :
c:python25xulrunner.exe
c:python25application.ini
I need to remove all special characters, punctuation and spaces from a string so that I only have letters and numbers.
When an 'r' or 'R' prefix is present,
a character following a backslash is
included in the string without change,
and all backslashes are left in the
string. For example, the string
literal r"n" consists of two
characters: a backslash and a
lowercase 'n'. String quotes can be
escaped with a backslash, but the
backslash remains in the string; for
example, r""" is a valid string
literal consisting of two characters:
a backslash and a double quote; r""
is not a valid string literal (even a
raw string cannot end in an odd number
of backslashes). Specifically, a raw
string cannot end in a single
backslash (since the backslash would
escape the following quote character).
Note also that a single backslash
followed by a newline is interpreted
as those two characters as part of the
string, not as a line continuation.
This has always confused me. It seems like this would be nicer:
What is the pythonic way to split a string before the occurrences of a given set of characters?