Splitting a semicolon-separated string to a dictionary, in Python
I have a string that looks like this:
I have a string that looks like this:
I’m looking for a way to split a text into n-grams.
Normally I would do something like:
What is an easy way in Python to format integers into strings representing thousands with K, and millions with M, and leaving just couple digits after comma?
So I’ve spent way to much time on this, and it seems to me like it should be a simple fix. I’m trying to use Facebook’s Authentication to register users on my site, and I’m trying to do it server side. I’ve gotten to the point where I get my access token, and when I go to:
Is there a quick way in Python to replace strings but, instead of starting from the beginning as replace does, starting from the end? For example:
I’m looking for a Python library for finding the longest common sub-string from a set of strings. There are two ways to solve this problem:
I have a column in a pandas DataFrame that I would like to split on a single space. The splitting is simple enough with DataFrame.str.split(' '), but I can’t make a new column from the last entry. When I .str.split() the column I get a list of arrays and I don’t know how to manipulate this to get a new column for my DataFrame.
I have a very large .txt file with hundreds of thousands of email addresses scattered throughout. They all take the format:
Is there a way to declare a string variable in python such that everything inside of it is automatically escaped, or has its literal character value?
Given a variable which holds a string is there a quick way to cast that into another raw string variable? The following code should illustrate what I’m after: line1 = "hurr..n..durr" line2 = r"hurr..n..durr" print(line1 == line2) # outputs False print(("%r"%line1)[1:-1] == line2) # outputs True The closest I have found so far is the … Read more