sed with multiple expression for in-place argument
I am trying to replace multiple words in a file by using
I am trying to replace multiple words in a file by using
Is there some better solution for printing unique lines other than a combination of sort and uniq?
Is there a Linux command like cat that joins files with the same number of lines horizontally?
I have a file that includes details about VMs running in a hypervisor. We run some command and redirect the output to a file. And the is data available in the below format.
I’ve been trying to write a simple bash script which I’ll be using to install an application and update it’s config file. I’m having hard time to have get it’s config file modified.
Using the regexp string, how can I remove all the lines before the first line that contains a match? e.g How can I change this:
How to filter out 2 lines for each line matching the grep regex?
this is my minimal test:
Say I have lines like this:
NOTE: This question is the complement of this Q&A: How to “grep” for line length in a given range?