Consider:
>>> numerator = 29 >>> denom = 1009 >>> print str(float(numerator/denom)) 0.0
How do I make it return a decimal?
Answers:
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Method 1
Until version 3, Python’s division operator, /, behaved like C’s division operator when presented with two integer arguments: it returns an integer result that’s truncated down when there would be a fractional part. See: PEP 238
>>> n = 29 >>> d = 1009 >>> print str(float(n)/d) 0.0287413280476
In Python 2 (and maybe earlier) you could use:
>>> from __future__ import division >>> n/d 0.028741328047571853
Method 2
In Python 2.x, division works like it does in C-like languages: if both arguments are integers, the result is truncated to an integer, so 29/1009 is 0. 0 as a float is 0.0. To fix it, cast to a float before dividing:
print str(float(numerator)/denominator)
In Python 3.x, the division acts more naturally, so you’ll get the correct mathematical result (within floating-point error).
Method 3
In your evaluation you are casting the result, you need to instead cast the operands.
Method 4
print str(float(numerator)/float(denom))
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