I have a folder that contains multiple files
folder
- artifact1.app
- artifact2.ext2
- artifact3.ext3
- …
My goal is to zip the file from outside this folder (so without using cd command) without including the folder dir.
zip -r ./folder/artifact.zip ./folder/artifact1.app
This command includes the folder dir in the final zip. Any hints?
Related question: Zip the contents of a folder without including the folder itself
Answers:
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Method 1
If you want to store all the files in folder under their name without a directory indication, you can use the -j option.
zip -j folder/artifact.zip folder/artifact1.app folder/artifact2.ext2 folder/artifact3.ext3
or
zip -j folder/{artifact.zip,artifact1.app,artifact2.ext2,artifact3.ext3}
If you have files in subdirectories, they won’t have any directory component in the archive either, e.g. folder/subdir/foo will be stored in the archive as foo.
But it would probably be easier to change to the directory. It’s almost exactly the same amount of typing as the brace method aboe. If you do that, if you include files in subdirectories, they’ll have their relative path from the directory you changed into, e.g. folder/subdir/foo will be stored as subdir/foo.
(cd folder && zip artifact.zip artifact1.app artifact2.ext2 artifact3.ext3)
For interactive use, you lose shell completion this way, because the shell doesn’t realize that you’ll be in a different directory when you run the zip command. To remedy that, issue the cd command separately. To easily go back to the previous directory, you can use pushd and popd.
pushd folder zip artifact.zip artifact1.app artifact2.ext2 artifact3.ext3 popd
If you want full control over the paths stored in a zip file, you can create a forest of symbolic links. Unless instructed otherwise, zip doesn’t store symbolic links.
All methods was sourced from stackoverflow.com or stackexchange.com, is licensed under cc by-sa 2.5, cc by-sa 3.0 and cc by-sa 4.0