How to import a module in Python with importlib.import_module

I’m trying to use importlib.import_module in Python 2.7.2 and run into the strange error.

Consider the following dir structure:

    a
    |
    + - __init__.py
      - b
        |
        + - __init__.py
          - c.py

a/b/__init__.py has the following code:

    import importlib

    mod = importlib.import_module("c")

(In real code "c"has a name.)

Trying to import a.b, yields the following error:

    >>> import a.b
    Traceback (most recent call last):
      File "", line 1, in 
      File "a/b/__init__.py", line 3, in 
        mod = importlib.import_module("c")
      File "/opt/Python-2.7.2/lib/python2.7/importlib/__init__.py", line 37, in   import_module
        __import__(name)
    ImportError: No module named c

What am I missing?

Thanks!

Answers:

Thank you for visiting the Q&A section on Magenaut. Please note that all the answers may not help you solve the issue immediately. So please treat them as advisements. If you found the post helpful (or not), leave a comment & I’ll get back to you as soon as possible.

Method 1

For relative imports you have to:

  • a) use relative name
  • b) provide anchor explicitly
    importlib.import_module('.c', 'a.b')

Of course, you could also just do absolute import instead:

importlib.import_module('a.b.c')

Method 2

I think it’s better to use importlib.import_module('.c', __name__) since you don’t need to know about a and b.

I’m also wondering that, if you have to use importlib.import_module('a.b.c'), why not just use import a.b.c?

Method 3

And don’t forget to create a __init__.py with each folder/subfolder (even if they are empty)


All methods was sourced from stackoverflow.com or stackexchange.com, is licensed under cc by-sa 2.5, cc by-sa 3.0 and cc by-sa 4.0

0 0 votes
Article Rating
Subscribe
Notify of
guest

0 Comments
Oldest
Newest Most Voted
Inline Feedbacks
View all comments
0
Would love your thoughts, please comment.x
()
x