How to show lines after each grep match until other specific match?

I know that by using the "-A NUM" switch I can print specific number of trailing lines after each match. I am just wondering if it’s possible to print trailing lines until a specific word is found after each match. e.g. When I search for “Word A” I want to see the line containing “Word A” and also the lines after it until the one containing “Word D”.

context:

Word A
Word B
Word C
Word D
Word E
Word F

command:

grep -A10 'Word A'

I need this output:

Word A
Word B
Word C
Word D

Answers:

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Method 1

It seems that you want to print lines between ‘Word A‘ and ‘Word D‘ (inclusive). I suggest you to use sed instead of grep. It lets you to edit a range of input stream which starts and ends with patterns you want. You should just tell sed to print all lines in range and no other lines:

sed -n -e '/Word A/,/Word D/ p' file

Method 2

why not use awk ?

awk '/Word A/,/Word D/' filename

Method 3

perl -lne 'print if /Word A/ .. /Word D/' file

or

cat file | perl -lne 'print if /Word A/ .. /Word D/'

All methods was sourced from stackoverflow.com or stackexchange.com, is licensed under cc by-sa 2.5, cc by-sa 3.0 and cc by-sa 4.0