Bitwise shift and the largest integer in Bash
This is an exploration question, meaning I’m not completely sure what this question is about, but I think it’s about the biggest integer in Bash. Anyhow, I’ll define it ostensively.
arithmetic
Check if $REPLY is in a range of numbers
I’m writing a shell script for Linux, using Bash, to translate any video-file into a MP4. For that, I’m using avconv with libvorbis for audio.
What is the rationale for the bash shell not warning you of arithmetic overflow etc.?
There are limits set for the arithmetic evaluation capabilities of the bash shell. The manual is succinct about this aspect of shell arithmetic but states:
Bash: double equals vs -eq
I am doing integer comparison in bash (trying to see if the user is running as root), and I found two different ways of doing it:
How to create a sequence with leading zeroes using brace expansion
When I use the following, I get a result as expected:
bash -e exits when let or expr evaluates to 0
I have a bash script that sets -e so the script will exit on any exit status != 0.
Why does “$(( ~33 ))” produce -34?
NOT x = −x − 1