xargs and vi – “Input is not from a terminal”
I have about 10 php.ini files on my system, located all over the place, and I wanted to quickly browse through them. I tried this command:
I have about 10 php.ini files on my system, located all over the place, and I wanted to quickly browse through them. I tried this command:
For example, a common alias I’ve seen in the ~/.bashrc file (or equivalents) is
I just want to implement if condition in awk. I created one file name : “simple_if” as below.
The output of the above command when passed through echo is:
There are seven kinds of expansion … The order of expansions is: brace expansion; tilde expansion, parameter and variable expansion, arithmetic expansion, and command substitution (done in a left-to-right fashion); word splitting; and filename expansion
One of the applications I use at work sometimes screws with my bash and so I don’t see my own input anymore. I.e.
For example, from this file:
Suppose you are working on a very old unix server where dos2unix, perl, tr, and sed are not present. How can you convert files from dos to unix format?
At the moment, if I download a compressed file, it could be any of a .tar.gz archive, a tar.bz2 arhive, a .zip archive or a .gz archive. And each time I do so, I have to remember what the command line options for that program are.
I am trying to copy files using secure copy(scp). I am trying to execute the following command but I get error due to the space in the absolute path of the location of the directory.