What’s the right way to quote $(command $arg)?
It’s high time to solve this conundrum that’s been bothering me for years…
It’s high time to solve this conundrum that’s been bothering me for years…
The read utility shall read a single line from standard input.
The following code best describes the situation. Why is the last line not outputting the trailing newline char? Each line’s output is shown in the comment. I’m using GNU bash, version 4.1.5
DIRNAME=”$(dirname $FILE)” will not do what you want if $FILE contains whitespace or globbing characters [?*.
I know I can solve this problem several ways, but I’m wondering if there is a way to do it using only bash built-ins, and if not, what is the most efficient way to do it.
./sample.txt Specimen_before.TXT ./sample.TXT Specimen_after.TXT
I would like to use variable substitution on a particular string that I access via a command. For example, if I copy something into my clipboard, I can access it like this.
As a simple example, I have a bunch of source code files. I want to store the “head” command output to a variable for all these files.
Some shell scripts I have come across use the following syntax when defining variables:
There are seven kinds of expansion … The order of expansions is: brace expansion; tilde expansion, parameter and variable expansion, arithmetic expansion, and command substitution (done in a left-to-right fashion); word splitting; and filename expansion