How to generate all permutations of a list?
How do you generate all the permutations of a list in Python, independently of the type of elements in that list?
permutation
permutations with unique values
itertools.permutations generates where its elements are treated as unique based on their position, not on their value. So basically I want to avoid duplicates like this:
Finding all possible permutations of a given string in python
I have a string. I want to generate all permutations from that string, by changing the order of characters in it. For example, say:
Generating permutations with repetitions
I know about itertools, but it seems it can only generate permutations without repetitions.
Shuffle DataFrame rows
I have the following DataFrame:
Generate a random derangement of a list
How can I randomly shuffle a list so that none of the elements remains in its original position?
Generate permutations of list with repeated elements
In Python, it is quite simple to produce all permutations of a list using the itertools module. I have a situation where the sequence I’m using only has two characters (i.e. '1122'). I want to generate all unique permutations.
Why does Python’s itertools.permutations contain duplicates? (When the original list has duplicates)
It is universally agreed that a list of n distinct symbols has n! permutations. However, when the symbols are not distinct, the most common convention, in mathematics and elsewhere, seems to be to count only distinct permutations. Thus the permutations of the list [1, 1, 2] are usually considered to be
[1, 1, 2], [1, 2, 1], [2, 1, 1]. Indeed, the following C++ code prints precisely those three: