How to grab the numebr with the end of “0” from the website?
I use BeaustifulSoup to grab some texts on the url”https://nature.altmetric.com/details/114136890″,and get such response
python-re
How to change inner text of HTML tags without removing them
Assuming I have “semi” HMTL string like
Pandas data validation with regex on one column
What I want to do is look for a specific pattern. 1 letter, a dash, followed by a year and letter like “A-2012A”. After that, the rest of the column’s value can be anything. I want to confirm this first part. And return a true/false value. Is it possible?
re.sub replace with matched content
Trying to get to grips with regular expressions in Python, I’m trying to output some HTML highlighted in part of a URL. My input is
re.findall not returning full match?
I have a file that includes a bunch of strings like “size=XXX;”. I am trying Python’s re module for the first time and am a bit mystified by the following behavior: if I use a pipe for ‘or’ in a regular expression, I only see that bit of the match returned. E.g.:
re.sub(“.*”, “, “(replacement)”, “text”) doubles replacement on Python 3.7
On Python 3.7 (tested on Windows 64 bits), the replacement of a string using the RegEx .* gives the input string repeated twice!