Terminating an infinite loop
I have a command that I want to have run again automatically each time it terminates, so I ran something like this:
signals
Why does closing terminal emulator window terminate a bash process with SIGHUP trap changed not to terminate?
In a bash shell in a terminal emulator window of lxterminal, I run
When does the system send a SIGTERM to a process?
My server program received a SIGTERM and stopped (with exit code 0). I am surprised by this, as I am pretty sure that there was plenty of memory for it. Under what conditions does linux (busybox) send a SIGTERM to a process?
What does a program do when it’s sent SIGKILL signal?
When I used killall -9 name to kill a program, the state become zombie. Some minutes later, it stopped really.
So, what’s happening during those minutes?
How does a Segmentation Fault work under-the-hood?
I can’t seem to find any information on this aside from “the CPU’s MMU sends a signal” and “the kernel directs it to the offending program, terminating it”.
limit find output AND avoid signal 13
I have a directory with ~1M files and need to search for particular patterns. I know how to do it for all the files:
How to stop the loop bash script in terminal?
For example,
“trap … INT TERM EXIT” really necessary?
Many examples for trap use trap ... INT TERM EXIT for cleanup tasks. But is it really necessary to list all the three sigspecs?
Is there any way to exit “less” follow mode without stopping other processes in pipe?
Often times I find myself in need to have the output in a buffer with all the features (scrolling, searching, shortcuts, …) and I have grown accustomed to less.
Bash script doesn’t see SIGHUP?
I’ve got the following script: