how can I add (subtract, etc.) two numbers with bash?
I can read the numbers and operation in with:
variable
In Bash scripting, what’s the meaning of ” $! “?
If I’m assigning a variable with
Why is the array empty after the while loop?
I try to initialize an array in bash-4.2 next way: ring=() ls -las | tail -n +4 | while read line > do > ring+=("$line") > echo ${ring[-1]} > done 3924 -rw-r–r– 1 username group 4015716 Mar 23 15:14 script.jar 4 -rw-r–r– 1 username group 9 Feb 29 12:40 rec.lst 5541 -rw-r–r– 1 username group … Read more
bash dynamic (variable) variable names
I want to dynamically create a sequence of strings by manipulate an array of elements and create some arithmetic procedure.
How to send variable to an inline shell-script?
I run the following script:
Circular name references in bash shell function, but not in ksh
I’m writing a set of shell functions that I want to have working in both Bash and KornShell93, but with Bash I’m running into a “circular name reference” warning.
Is it possible to print the content of the content of a variable with shell script? (indirect referencing)
Let’s suppose I’ve declared the following variables:
When should one use $( ) in defining variables
Some shell scripts I have come across use the following syntax when defining variables:
What’s the purpose of adding a prefix on both sides of a shell variable comparison to a string literal?
I have encountered comparisions of variables to string literals multiple times over the years which had one character prefixing the variable and the literal, e.g.
how to understand the output of “echo $-“?
How to understand the output of echo $-? It looks like some kind of flag characters. I can’t get a clue by googling.