NumPy chained comparison with two predicates
In NumPy, I can generate a boolean array like this:
In NumPy, I can generate a boolean array like this:
I’ve created a subclass of numpy ndarray following the numpy documentation. In particular, I have added a custom attribute by modifying the code provided.
Let’s say I have the following array :
Im trying to create a basic exe using cx_Freeze. It works for .py programs that don’t have numpy but I can’t get one made correctly with numpy.
I have a 2d numpy array. I want to take the average value of the n nearest entries to each entry, just like taking a sliding average over a one-dimensional array. What is the cleanest way to do this?
I’m writing some moderately performance critical code in numpy.
This code will be in the inner most loop, of a computation that’s run time is measured in hours.
A quick calculation suggest that this code will be executed up something like 10^12 times, in some variations of the calculation.
at(a, indices, b=None)
I have a Timeseries (s) which need to be processed recursively to get a timeseries result (res). Here is my sample code:
Let me start by telling that what I get may not be what I expect and perhaps you can help me here. I have the following data:
If I have a numpy array like this: [2.15295647e+01, 8.12531501e+00, 3.97113829e+00, 1.00777250e+01] how can I move the decimal point and format the numbers so I end up with a numpy array like this: [21.53, 8.13, 3.97, 10.08] np.around(a, decimals=2) only gives me [2.15300000e+01, 8.13000000e+00, 3.97000000e+00, 1.00800000e+01] Which I don’t want and I haven’t found another … Read more